17.3x^2=12-6x

Solution for 17.3x^2=12-6x equation:

17.3x^2=12-6x

We move all terms to the left:

17.3x^2-(12-6x)=0

We add all the numbers together, and all the variables

17.3x^2-(-6x+12)=0

We get rid of parentheses

17.3x^2+6x-12=0

a = 17.3; b = 6; c = -12;
Δ = b2-4ac
Δ = 62-4·17.3·(-12)
Δ = 866.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-\sqrt{866.4}}{2*17.3}=\frac{-6-\sqrt{866.4}}{34.6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+\sqrt{866.4}}{2*17.3}=\frac{-6+\sqrt{866.4}}{34.6}
$